Let S_1=\{z_1 \in C: z_1-3|=\frac{1}{2}\} and S_2=\{z_2 \in C: z_2-| z_2+1|| = z_2+| z_2-1|| \}. Then, for z_1 \in S_1 and z_2 \in S_2, the least value of z_2-z_1| is : [28-Jul-2022-Shift-1]

JEE Mains 28-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 15 of 90

Marks: +1, -0

Let S1={z1∈C:z1−3|=‌

} and S2={z2∈C:z2−|z2+1||=z2+|z2−1||}. Then, for z1∈S1 and z2∈S2, the least value of z2−z1| is :

[28-Jul-2022-Shift-1]

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