Let f(x)=2+|x|-|x-1|+|x+1|, x \in R. Consider (S1): f^{'}(-\frac{3}{2})+f^{'}(-\frac{1}{2})+f^{'}(\frac{1}{2})+f^{'}(\frac{3}{2})=2 (S2) : \int_{-2}^2 f(x) {\d} x=12 Then, [27-Jul-2022-Shift-2]

Correct Answer is : only (S2) is correct

JEE Mains 27-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 6 of 90

Marks: +1, -0

Let f(x)=2+|x|−|x−1|+|x+1|,x∈R.
Consider
(S1): f′(−‌

)+f′(−‌

)+f′(‌

)=2
(S2) :

∫

−2

2f(x)dx=12
Then,

[27-Jul-2022-Shift-2]

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