JEE Mains 27-July-2022 Shift 2 Solved Paper

Section: Physics
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Question : 31 of 90
 
Marks: +1, -0
An expression of energy density is given by u=‌
α
β
‌sin
(‌
αx
kt
)
, where α,β are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of β will be :
[27-Jul-2022-Shift-2]
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