JEE Mains 27-July-2022 Shift 1 Solved Paper

Let initial moles of reactant taken =n
Total moles obtained for benzene sulphonic acid (with % yield =60%)=0.6n
Moles of benzene sulphonic acid before reaction II=0.6n
Moles obtained for phenol (with \% yield =50% ) =0.6×0.5n=0.3n
So over all \% yield of complete reaction =‌

0.3n

n

×100=30