An electron (mass {\m} ) with an initial velocity \overrightarrow{v}=v_0 i(v_0 > 0) is moving in an electric field \overrightarrow{E}=-E_0 \stackrel{\^}{i}(E_0 > 0) where E_0 is constant. If at {\t}=0 de Broglie wavelength is \lambda_0=\frac{h}{m v_0}, then its de Broglie wavelength after time t is given by [27-Jul-2022-Shift-1]

Correct Answer is : λ0(1+eE0tmv0)

\lambda_0(1+\frac{e E_0 t}{m v_0})

{\lambda_0}/{(1+\frac{e E_0 t}{m v_0})}

JEE Mains 27-July-2022 Shift 1 Solved Paper

Section: Physics

Question : 47 of 90

Marks: +1, -0

An electron (mass m ) with an initial velocity

→

=v0i(v0>0) is moving in an electric field

→

=−E0

(E0>0) where E0 is constant. If at t=0 de Broglie wavelength is λ0=‌

mv0

, then its de Broglie wavelength after time t is given by

[27-Jul-2022-Shift-1]

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