JEE Mains 27-July-2022 Shift 1 Solved Paper

Among the 5 digit numbers,
First number divisible by 7 is 10003 and last is 99995 .
⇒ Number of numbers divisible by 7 .
=‌

99995−10003

7

+1
=12857
First number divisible by 35 is 10010 and last is 99995.
⇒ Number of numbers divisible by 35
=‌

99995−10010

35

+1
=2572
Hence number of number divisible by 7 but not by 5
=12857−2572
=10285
9P.=‌

10285

90000

×9
=1.0285