An ice cube of dimensions 60 {\cm} \times 50 {\cm} \times 20 {\cm} is placed in an insulation box of wall thickness 1 {\cm}. The box keeping the ice cube at 0^{\circ} {\C} of temperature is brought to a room of temperature 40^{\circ} {\C} The rate of melting of ice is approximately : (Latent heat of fusion of ice is 3.4 \times 10^5 {\J} {\kg}^{-1} and thermal conducting of insulation wall is .0.05 {\Wm}^{-1 \circ} {\C}^{-1}) [26-Jul-2022-Shift-2]

Correct Answer is : 61×10−5kgs−1

61 \times 10^{-3} {\kg} {\s}^{-1}

61 \times 10^{-5} {\kg} {\s}^{-1}

30 \times 10^{-5} {\kg} {\S}^{-1}

JEE Mains 26-July-2022 Shift 2 Solved Paper

Section: Physics

Question : 41 of 90

Marks: +1, -0

An ice cube of dimensions 60‌cm×50‌cm×20‌cm is placed in an insulation box of wall thickness 1‌cm. The box keeping the ice cube at 0∘C of temperature is brought to a room of temperature 40∘C The rate of melting of ice is approximately :
(Latent heat of fusion of ice is 3.4×105Jkg−1 and thermal conducting of insulation wall is .0.05Wm−1∘C−1)

[26-Jul-2022-Shift-2]

61×10−3‌kg‌s−1
61×10−5‌kg‌s−1
208‌kg‌s−1
30×10−5‌kg‌S−1

Validate

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