JEE Mains 26-July-2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 16 of 90

Marks: +1, -0

If 0<x<‌

1

√2

and ‌

sin−1x

α

=‌

cos−1x

β

, then the value of sin(‌

2πα

α+β

) is

[26-Jul-2022-Shift-2]

4√(1−x2)(1−2x2)
4x√(1−x2)(1−2x2)
2x√(1−x2)(1−4x2)
4√(1−x2)(1−4x2)

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