JEE Mains 26-July-2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 12 of 90

Marks: +1, -0

The equation of a common tangent to the parabolas y=x2 and y=−(x−2)2 is

[26-Jul-2022-Shift-2]

y=4(x−2)
y=4(x−1)
y=4(x+1)
y=4(x+2)

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