JEE Mains 26-July-2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 10 of 90

Marks: +1, -0

Let the solution curve y=f(x) of the differential equation ‌

dy

dx

+‌

xy

x2−1

=‌

x4+2x

√1−x2

,x∈(−1,1) pass through the origin. Then

‌

√3

2

∫

−‌

√3

2

f(x)dx is equal to

[26-Jul-2022-Shift-2]

‌
π
3
−‌
1
4
‌
π
3
−‌
√3
4
‌
π
6
−‌
√3
4
‌
π
6
−‌
√3
2

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