The magnetic field of a plane electromagnetic wave is given by : \overrightarrow{ {\B}=2 \times 10^{-8} \sin (0.5 \times 10^3 x+1.5 \times 10^{11} {\t}) \stackrel{\^}{j} {\T} The amplitude of the electric field would be : [26-Jul-2022-Shift-1]

Correct Answer is : 6Vm−1 along z-axis

2 \times 10^{-8} {\Vm}^{-1} along z-axis

JEE Mains 26-July-2022 Shift 1 Solved Paper

Section: Physics

Question : 36 of 90

Marks: +1, -0

The magnetic field of a plane electromagnetic wave is given by :

→

=2×10−8‌sin(0.5×103x+1.5×1011t)‌

‌T
The amplitude of the electric field would be :

[26-Jul-2022-Shift-1]

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