JEE Mains 25-July-2022 Shift 2 Solved Paper

Section: Chemistry
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Question : 84 of 90
 
Marks: +1, -0
While performing a thermodynamics experiment, a student made the following observations.
HCl+NaOH→NaCl+H2O∆H=−57.3kJmol−1
CH3COOH+NaOH→CH3COONa+H2O∆H=−55.3kJmol−1
The enthalpy of ionization of CH3COOH as calculated by the student is _____kJmol−1. (nearest integer)
[25-Jul-2022-Shift-2]
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