Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength \lambda. The value of principal quantum number ' n ' of the excited state will be : (R : Rydberg constant) [25-Jul-2022-Shift-2]

Correct Answer is : √λRλR−1

\sqrt{\frac{\lambda {R}{\lambda-1}}

\sqrt{ {\lambda {R}/{\lambda {R}-1}}

\sqrt{\frac{\lambda}{\lambda {R} .-1}}

\sqrt{\frac{\lambda R^{2}{\lambda R-1}}

JEE Mains 25-July-2022 Shift 2 Solved Paper

Section: Physics

Question : 50 of 90

Marks: +1, -0

Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength λ. The value of principal quantum number ' n ' of the excited state will be : (R : Rydberg constant)

[25-Jul-2022-Shift-2]

√‌
λR
λ−1
√‌
λR
λR−1
√‌
λ
λR.−1
√‌
λR2
λR−1

Validate

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