JEE Mains 25-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 6 of 90

Marks: +1, -0

If the absolute maximum value of the function f(x)=(x2−2x+7)e(4x3−12x2−180x+31) in the interval [−3,0] is f(α), then :

[25-Jul-2022-Shift-1]

Go to Question:

Prev Question

Next Question