Let the equation of two diameters of a circle x^{2}+y^{2}-2 x+2 f y+1=0 be 2 p x-y=1 and 2 x+p y=4 p. Then the slope {m} \in(0, \infty) of the tangent to the hyperbola 3 x^{2}-y^{2}=3 passing through the centre of the circle is equal to [25-Jul-2022-Shift-1]

JEE Mains 25-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 28 of 90

Marks: +1, -0

Let the equation of two diameters of a circle x2+y2−2x+2fy+1=0 be 2px−y=1 and 2x+py=4p. Then the slope m∈(0,∞) of the tangent to the hyperbola 3x2−y2=3 passing through the centre of the circle is equal to

[25-Jul-2022-Shift-1]

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