Match List I with List II : A. Gauss'sLaw inElectrostat ics I. ∮ \overrightarrow{E} \cdot d \overrightarrow{l}=-\frac{d \phi_B}{d t} B. Faraday'sLaw II. ∮ \overrightarrow{ {\B} \cdot {\d} \overrightarrow{ {\A}=0 C. Gauss'sLaw inMagnetism III. ∮ \overrightarrow{B} . d \overrightarrow{l}=\mu_0 i_c+\mu_0 \in_0 \frac{d \phi_E}{d t} D. Ampere-MaxwellLaw IV. ∮ \overrightarrow{ {\E} \cdot {\d} \overrightarrow{ { s}=\frac{ {\q}}{E_0} Choose the correct answer from the options given below : [25-Jan-2023 Shift 2]

Correct Answer is : A-IV, B-I, C-II, D-III

JEE Mains 25-Jan-2023 Shift 2 Solved Paper

Section: Physics

Question : 6 of 90

Marks: +1, -0

Match List I with List II :

A. Gauss'sLaw inElectrostat ics

I. ∮

→

⋅d

→

=−‌

dφB

B. Faraday'sLaw

II. ∮

→

⋅d

→

C. Gauss'sLaw inMagnetism

III. ∮

→

=µ0ic+µ0∈0‌

dφE

D. Ampere-MaxwellLaw

IV. ∮

→

⋅d

→

=‌

Choose the correct answer from the options given below :

[25-Jan-2023 Shift 2]

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