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JEE Mains 25-Jan-2023 Shift 2 Solved Paper

Section: Chemistry
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Question : 57 of 90
 
Marks: +1, -0
Pt( s)‌H2(g)(1‌bar)|H+(aq)(1M)||M3+(aq),M+(aq)|Pt( s)
The E‌cell ‌ for the given cell is 0.1115V at 298K when ‌
[M+(aq)]
[M3+(aq)]
=10a
The value of a is _________
Given : EθM3+∕M+=0.2V
‌
2.303‌RT
F
=0.059V
[25-Jan-2023 Shift 2]
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