The distance of the point (6,-2 \sqrt{2}) from the common tangent {\y}= {\mx}+ {\c}, {\m} > 0, of the curves {\x}=2 {\y}^2 and {\x}=1+ {\y}^2 is [25-Jan-2023 Shift 1]

JEE Mains 25-Jan-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 73 of 90

Marks: +1, -0

The distance of the point (6,−2√2) from the common tangent y=mx+c,m>0, of the curves x=2y2 and x=1+y2 is

[25-Jan-2023 Shift 1]

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