The points of intersection of the line a x+b y=0, (a \neq b) and the circle x^2+y^2-2 x=0 are {\A}(\alpha, 0) and {\B}(1, \beta). The image of the circle with {\AB} as a diameter in the line {\x}+ {\y}+2=0 is : [25-Jan-2023 Shift 1]

Correct Answer is : x2+y2+5x+5y+12=0

JEE Mains 25-Jan-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 65 of 90

Marks: +1, -0

The points of intersection of the line ax+by=0, (a≠b) and the circle x2+y2−2x=0 are A(α,0) and B(1,β). The image of the circle with AB as a diameter in the line x+y+2=0 is :

[25-Jan-2023 Shift 1]

x2+y2+5x+5y+12=0
x2+y2+3x+5y+8=0
x2+y2+3x+3y+4=0
x2+y2−5x−5y+12=0

Validate

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