Let y=y(x) be the solution curve of the differential equation \frac{d y}{d x}=\frac{y}{x} (1+x y^2 (1+\log _e x) ), x > 0, y(1) =3. Then \frac{y^2(x)}{9} is equal to : [25-Jan-2023 Shift 1]

Correct Answer is : x25−2x3(2+logex3)

\frac{x^2}{5-2 x^3 (2+\log _e x^3) }

\frac{x^2}{2 x^3 (2+\log _e x^3) -3}

\frac{x^2}{3 x^3 (1+\log _e x^2) -2}

\frac{x^2}{7-3 x^3 (2+\log _e x^2) }

JEE Mains 25-Jan-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 63 of 90

Marks: +1, -0

Let y=y(x) be the solution curve of the differential equation ‌

=‌

(1+xy2(1+logex)), x>0,y(1)=3. Then ‌

y2(x)

is equal to :

[25-Jan-2023 Shift 1]

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