Consider the cell {\Pt}( { s}) | {\H}_2( { s})( {\latm}) {\H}^{+} ( {\aq}, [ {\H}^{+}] =1) {\Fe}^{3+}( {\aq}), {\Fe}^{2+}( {\aq}) ∣ {\Pt}( { s}) Given: {\E}_{ {\Fe}^{3+\/ \/ {\Fe}^{2+}}}^{\circ}=0.771 {\V} and {\E}_{ {\H}^{+} \/ \frac{1}{2} {\H}_2}^{\circ}=0 {\V}, {\T}=298 {\K} If the potential of the cell is 0.712 {\V} the ratio of concentration of {\Fe}^{2+} to {\Fe}^{2+} is ________ (Nearest integer) [25-Jan-2023 Shift 1]

JEE Mains 25-Jan-2023 Shift 1 Solved Paper

Section: Chemistry

Question : 60 of 90

Marks: +1, -0

Consider the cell
Pt( s)|H2( s)(latm)H+(aq,[H+]=1)
Fe3+(aq),Fe2+(aq)∣Pt( s)
Given: EFe3+∕∕Fe2+∘=0.771V and EH+∕‌

H2∘=0V,T=298K
If the potential of the cell is 0.712V the ratio of concentration of Fe2+ to Fe2+ is ________ (Nearest integer)

[25-Jan-2023 Shift 1]

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