JEE Mains 24-Jan-2023 Shift 2 Solved Paper

C6H5‌COOH

(WA)

+

NaOH

(SB)

→

C6H5‌COONa

(Salt)

+H2O(A) → (B) Free H+ions are replaced by Na⊕ which decreases conductance.
(B) → (C) Un-dissociated benzoic acid reacts with NaOH and forms salt which increases ions & conductance increases.
(C) → (D) After equivalence point at (3), NaOH added further increases Na⊕&OH⊙ ions which further increases the conductance.