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Question : 63 of 90
Marks:
+1,
-0
Solution:
‌=(1,−1,−2),=(2,1,−1),⋅=2‌×=+λ...............⋅(1)‌‌ Taking dot with ‌‌ in ‌(1)‌⋅(×)=⋅+λ⋅‌⇒0=⋅+2λ‌‌ Taking dot with ‌‌ in ‌(1)‌⋅(×)=⋅+λ⋅‌⇒0=(2−1+2)+λ(6)‌λ=−‌‌⇒⋅=−2λ=1
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