JEE Mains 2020 Model Paper 6 New Pattern
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Question : 4 of 75
Marks:
+1,
-0
Let f n ( θ ) = tan
( 1 + sec θ ) ( 1 + sec 2 θ ) ( 1 + sec 4 θ ) . . . ( 1 + sec 2 n θ ) f 2 (
) + f 3 (
) + f 4 (
) + f 5 (
)
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