When an ac source of emf e=E_0\sin (100t) is connected across a circuit, the phase difference between emf e and current i in the circuit is observed to be \pi / 4, as shown in the figure. If the circuit consists possibly only of R-C or R-L or L-C in series, then the relationship between the two elements.

Correct Answer is : R=1kΩ,C=10µF

JEE Mains 2020 Model Paper 6 New Pattern

Question : 31 of 75

Marks: +1, -0

When an ac source of emf e=E0‌sin(100t) is connected across a circuit, the phase difference between emf e and current i in the circuit is observed to be

, as shown in the figure. If the circuit consists possibly only of R-C or R-L or L-C in series, then the relationship between the two elements.

R=1kΩ,C=10µF
R=1kµ,C=1µF
R=1kΩ,L=10H
R=1kΩ,L=1H

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