JEE Mains 2020 Model Paper 5 New Pattern

_____________n = 4
____________ n = 3
____________ n = 2
____________ n = 1
Since, at n = 1, the population of electrons is maximum at ground state. So, maximum excitation will take place from n = 1 to n = 2.
Hence n = 2 is the possible excited state
∴ Energy of 'H' atom, E=−13.6×

Z2

n2

eV=−3.4eV