JEE Mains 2020 Model Paper 3 New Pattern

For hydrogen electrode, oxidation half reaction is

H2

(1‌atm)

→

2H+

(At‌pH‌10)

+2e−
If pH = 10 ;
H+ = 1 × 10−pH = 1×10−10
For Nernst equation , Ecell = E°cell−

0.0591

2

‌log

[H+]

pH2

For hydrogen electrode, E°cell = 0
Ecell = −

0.0591

2

‌log

(10−10)2

1

= +

0.0591

2

‌log‌

1

10−10

= 0.0591 log 1010
= 0.0591 × 10
= 0.59 V