JEE Mains 2020 Model Paper 3 New Pattern

In time t, distance travelled by 1st particle = υt and distance travelled by 2nd paricle
= 0+

1

2

at2 =

1

2

a2
∴ the distance between them at time t is x = υt−

1

2

at2

dx

dt

= υ - at ;
For x to be maximum

dx

dt

= 0 ⇒ υ - at = 0
∴ t =

υ

a

i.e., at time t =

υ

a

, distance x is maximum.
maximum distance
xmx = υ(

υ

a

)−

1

2

a(

υ

a

)2 =

υ2

2a