JEE Mains 2020 Model Paper 1 New Pattern

y = sin2x−2sinx = sin x (sin x - 2)
y = 0
∴ sin x = 0
∴ x = 0 , π , 2π
Also sin x - 2 < 0
∴ y > 0 if sin x < 0
∴ Graph of the function is shown in the figure:
The required area = The shaded area
=
=
=
= |

1

2

π−4|+

2π−π

2

+4
= (4−

π

2

)+4+

π

2

= 8 sq. units.