JEE Mains 15-Apr-2023 Shift 1 Solved Paper
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Let x = x ( y ) be the solution of the differential equation 2 ( y + 2 ) log e ( y + 2 ) dx + ( x + 4 − 2 log e ( y + 2 ) ) dy = 0 , y > − 1 with x ( e 4 − 2 ) = 1 . Then x ( e 9 − 2 ) is equal to
[15-Apr-2023 shift 1]
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