Let the system of linear equations -x+2 y-9 z=7 -x+3 y+7 z=9 -2 x+y+5 z=8 -3 x+y+13 z=\lambda has a unique solution {\x}=\alpha, {\y}=\beta, {\z}=\gamma. Then the distance of the point (\alpha, \beta, \gamma) from the plane 2 {\x}-2 {\y}+ {\z}=\lambda is [15-Apr-2023 shift 1]

JEE Mains 15-Apr-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 17 of 90

Marks: +1, -0

Let the system of linear equations
‌−x+2y−9z=7
‌−x+3y+7z=9
‌−2x+y+5z=8
‌−3x+y+13z=λ
has a unique solution x=α,y=β,z=γ. Then the distance of the point (α,β,γ) from the plane 2x−2y+z=λ is

[15-Apr-2023 shift 1]

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