20 {\mL} of 0.1 {\M} {\NaOH} is added to 50 {\mL} of 0.1 {\M} acetic acid solution. The {\pH} of the resulting solution is _______ \times 10^{-2} (Nearest integer) \text{ Given : } {\pKa} ( {\CH}_3 {\COOH}) =4.76 \log 2=0.30 \log 3=0.48 [13-Apr-2023 shift 2]

JEE Mains 13-Apr-2023 Shift 2 Solved Paper

Section: Chemistry

Question : 83 of 90

Marks: +1, -0

20‌mL of 0.1M‌NaOH is added to 50‌mL of 0.1M acetic acid solution. The pH of the resulting solution is _______ ×10−2 (Nearest integer)
‌‌ Given : ‌pKa(CH3‌COOH)=4.76
‌log‌2=0.30
‌log‌3=0.48

[13-Apr-2023 shift 2]

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