JEE Mains 13-Apr-2023 Shift 2 Solved Paper

In steady state, no current will pass through capacitor hence capacitor will act as open circuit.
‌i2=0
‌i1=‌

3

6+4

=‌

3

10

A
Potential difference on 6Ω resistor =6×‌

3

10

=1.8 volt capacitor will have same potential so charge
=cv=4×1.8=7.2µc