JEE Mains 13-Apr-2023 Shift 1 Solved Paper

Section: Mathematics
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Question : 2 of 90
 
Marks: +1, -0
Among
(S1):
lim
n→∞
‌
1
n2
(2+4+6+.....+2n)
=1

(S2):
lim
n→∞
‌
1
n16
(115+215+315+.....+n15)
=‌
1
16

[13-Apr-2023 shift 1]
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