Let \alpha, \beta be the roots of the quadratic equation x^2+\sqrt{6} x+3=0. Then {\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}/{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}} is equal to [12-Apr-2023 shift 1]

JEE Mains 12-Apr-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 9 of 90

Marks: +1, -0

Let α,β be the roots of the quadratic equation x2+√6x+3=0. Then ‌

α23+β23+α14+β14

α15+β15+α10+β10

is equal to

[12-Apr-2023 shift 1]

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