{\H}_3 {\C}- {\CH}_2- {\CH}_{|}_{\OH}- {\CH}_3 \stackrel{\text{ (ii) }{ {──\xrightarrow {\Mg} \text{, Dry ether }}}^{(\i) {\NaI}, {\H}_3 {\PO}_4}_{(\iii) \D_2\O}{[ {\X}]}_{\Product} Product [ {\X}] formed in the above reaction is: [11-Apr-2023 shift 2]

Correct Answer is : H3C−CH2−CH|D−CH3

{\H}_3 {\C}- {\CH}_2- {\CH}_{|}_{\D}- {\CH}_3

{\H}_3 {\C}- {\CH}_2- {\CH}= {\CH}_2

{\H}_3 {\C}- {\CH}= {\CH}- {\CH}_3

{\H}_3 {\C}- {\CH}_2- \stackrel{|}{\C}^{\H}_{|}_{\OH}- {\CH}_3

JEE Mains 11-Apr-2023 Shift 2 Solved Paper

Section: Chemistry

Question : 67 of 90

Marks: +1, -0

H3C−CH2−

−CH3

(i)‌NaI,H3PO4

‌ (ii) ‌Mg‌, Dry ether ‌

─────────▶

(iii)D2O

[X]

Product

Product [X] formed in the above reaction is:

[11-Apr-2023 shift 2]

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