Let f and g be two functions defined by f(x)={\\begin{array}{ccc}x+1 & x &lt\ 0 \ |x-1| &\end{array} , x \geq 0}. and g(x)={\\begin{array}{cccc}x+1 & & x &lt\ 0 \ 1 & & x \geq 0\end{array}. Then (gof) (x) is [11-Apr-2023 shift 2]

Correct Answer is : continuous everywhere but not differentiable exactly at one point

continuous everywhere but not differentiable at {\x}=1

continuous everywhere but not differentiable exactly at one point

JEE Mains 11-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 4 of 90

Marks: +1, -0

Let f and g be two functions defined by f(x)={

x+1	x<0
\|x−1\|,	x≥0

. and g(x)={

x+1	‌	x<0
1	‌	x≥0

. Then (gof) (x) is

[11-Apr-2023 shift 2]

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x+2	x<−1
1	x≥−1