JEE Mains 11-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

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Question : 12 of 90

Marks: +1, -0

Let y=y(x) be the solution of the differential equation ‌

dy

dx

+‌

5

x(x5+1)

y=‌

(x5+1)2

x7

,x>0. If y(1)=2, then y(2) is equal to

[11-Apr-2023 shift 2]

‌
693
128
‌
637
128
‌
697
128
‌
679
128

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