A metallic surface is illuminated with radiation of wavelength \lambda, the stopping potential is V_0. If the same surface is illuminated with radiation of wavelength 2 \lambda, the stopping potential becomes \frac{V_0}{4}. The threshold wavelength for this metallic surface will be [11-Apr-2023 shift 1]

JEE Mains 11-Apr-2023 Shift 1 Solved Paper

Section: Physics

Question : 49 of 90

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A metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V0. If the same surface is illuminated with radiation of wavelength 2λ, the stopping potential becomes ‌

. The threshold wavelength for this metallic surface will be

[11-Apr-2023 shift 1]

‌
3
2
λ
4λ
3λ
‌
λ
4

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