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Question : 30 of 90
Marks:
+1,
-0
Solution:
Let ℓ=(0+0+0)+γ(a+b+c)=γ(a+b+c)a+b+c=||=(2−6)−(1−6)+(2−4)=−4−5−2ℓ=γ(−4+5−2)P is intersection of
ℓ and
ℓ1−4γ=1+λ,5γ=−11+2λ,−2γ=−7+3λBy solving these equation
γ=−1,P(4,−5,2)Let
Q(−1+2µ,2µ,1+µ)⋅(2+2+)=0−2+4µ+4µ+1+µ=09µ=1µ=Q(,,)9(α+β+γ)=9(++)=5
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