If the area of the region \{( {\x}, {\y}):{| {\x}^2-2 |} \leq {\x}\} is {\A}, then 6 {\A}+16 \sqrt{2} is equal to ______. [10-Apr-2023 shift 2]

JEE Mains 10-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 25 of 90

Marks: +1, -0

If the area of the region {(x,y):|x2−2|≤x} is A, then 6A+16√2 is equal to ______.

[10-Apr-2023 shift 2]

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