In the figure, \theta_1+\theta_2=\frac{\pi}{2} and \sqrt{3}( {\BE})=4( {\AB}). If the area of \triangle {\CAB} is 2 \sqrt{3}-3 unit ^2, when \frac{\theta_2}{\theta_1} is the largest, thenthe perimeter (in unit) of \triangle {\CED} is equal to _______. [10-Apr-2023 shift 2]

JEE Mains 10-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 22 of 90

Marks: +1, -0

In the figure, θ1+θ2=‌

and √3(BE)=4(AB). If the area of △CAB is 2√3−3 unit ‌2, when ‌

θ2

θ1

is the largest, thenthe perimeter (in unit) of △CED is equal to _______.

[10-Apr-2023 shift 2]

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