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JEE Mains 10-Apr-2023 Shift 2 Solved Paper

Section: Mathematics
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Question : 14 of 90
 
Marks: +1, -0
For α,β,γ,δ∈N, if ∫((‌
x
e
)2x+(‌
e
x
)2x)loge‌xdx=‌
1
α
(‌
x
e
)βx−‌
1
γ
(‌
e
x
)δx+C, where e=
∞
∑
n=0
‌
1
n!
 and C is constant of integration, then α+2β+3γ−4δ is equal to
[10-Apr-2023 shift 2]
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