Let the number (22)^{2022}+(2022)^{22} leave the remainder \alpha when divided by 3 and \beta when divided by 7 . Then (\alpha^2. +\beta^2) is equal to [10-Apr-2023 shift 2]

JEE Mains 10-Apr-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 12 of 90

Marks: +1, -0

Let the number (22)2022+(2022)22 leave the remainder α when divided by 3 and β when divided by 7 . Then (α2. +β2) is equal to

[10-Apr-2023 shift 2]

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