JEE Mains 10-Apr-2023 Shift 1 Solved Paper

There can be infinitely many parabolas through given points.
Let parabola x2=−4a(y−1)Passes through (1,0)
‌∴b=−4a(−1)⇒a=‌

1

4

‌∴x2=−(y−1)
Now area covered by parabola =

0

∫

−1

(1−x2)‌dx
‌=(x−‌

x3

3

)1b=(0−0)−{−1+‌

1

3

}
‌=‌

2

3

Required Area = Area of sector −{ Area of square - Area covered by Parabola }
‌=‌

π

4

−{1−‌

2

3

}
‌=‌

π

4

−‌

1

3

‌∴12(π−4A)=12[π−4(‌

π

4

−‌

1

3

)]
‌=12[π−π+‌

4

3

]
‌=16