Let \alpha x=\exp (x^\beta y^\gamma) be the solution of the differential equation 2 {\x}^2 {\y} d y- (1-x y^2) \dx=0, x > 0, y(2)=\sqrt{\log _{ {\e} 2}. Then \alpha+\beta-\gamma equals : [1-Feb-2023 Shift 2]

JEE Mains 1-Feb-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 74 of 90

Marks: +1, -0

Let αx=exp(xβyγ) be the solution of the differential equation 2x2ydy−(1−xy2)‌dx=0, x>0,y(2)=√loge2. Then α+β−γ equals :

[1-Feb-2023 Shift 2]

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