Let S= \{x \in R: 0 < x < 1. and 2 \tan ^{-1} (\frac{1-x}{1+x}) =\cos ^{-1} (\frac{1-x^2}{1+x^2}) \}. If {\n}( {\S}) denotes the number of elements in {\S} then : [1-Feb-2023 Shift 2]

Correct Answer is : n(S)=1 and the element in S is less than 12.

{\n}( {\S})=2 and only one element in {\S} is less then \frac{1}{2}.

{\n}( {\S})=1 and the element in {\S} is more than \frac{1}{2}.

n(S)=1 and the element in S is less than \frac{1}{2}.

JEE Mains 1-Feb-2023 Shift 2 Solved Paper

Section: Mathematics

Question : 62 of 90

Marks: +1, -0

Let S={x∈R:0<x<1. and 2tan−1(‌

1−x

1+x

)=cos−1(‌

1−x2

1+x2

)}. If n(S) denotes the number of elements in S then :

[1-Feb-2023 Shift 2]

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