JEE Mains 1-Feb-2023 Shift 2 Solved Paper
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Question : 56 of 90
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The molality of a 10 % ( v ∕ v ) CCl 4 x x = × 10 − 2 M
[Given : molar mass ofBr 2 = 160 g mol − 1
atomic mass ofC = 12 g mol − 1
atomic mass ofCl = 35.5 g mol − 1
density of dibromine= 3.2 g cm − 3
density ofCCl 4 = 1.6 g cm − 3
[Given : molar mass of
atomic mass of
atomic mass of
density of dibromine
density of
[1-Feb-2023 Shift 2]
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