A cubical volume is bounded by the surfaces x=0, x=a, y=0, y=a, z=0, z=a. The electric field in the region is given by \overrightarrow{ {\E}= {\E}_0 \times { {\i}}^{\^}. Where {\E}_0=4 \times 10^4 {\NC}^{-1} {\m}^{-1}. If {\a}=2 {\cm}, the charge contained in the cubical volume is {\Q} \times 10^{-14} {\C}. The value of {\Q} is ______. Take E_0=9 \times 10^{-12} {\C}^2 \/ {\Nm}^2 ) [1-Feb-2023 Shift 2]

JEE Mains 1-Feb-2023 Shift 2 Solved Paper

Section: Physics

Question : 29 of 90

Marks: +1, -0

A cubical volume is bounded by the surfaces x=0,x=a,y=0,y=a,z=0,z=a. The electric field in the region is given by

→

=E0×‌

. Where E0=4×104NC−1m−1. If a=2‌cm, the charge contained in the cubical volume is Q×10−14C. The value of Q is ______.
Take E0=9×10−12C2∕Nm2 )

[1-Feb-2023 Shift 2]

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