If {\y}= {\y}( {\x}) is the solution curve of the differential equation { {\dy}}/{ {\dx}}+ {\y} \tan {\x}= {\x} \sec {\x}, 0 \leq {\x} \leq \frac{\pi}{3}, y(0)=1, then y (\frac{\pi}{6}) is equal to [1-Feb-2023 Shift 1]

Correct Answer is : π12−√32loge(2e√3)

\frac{\pi}{12}- {\sqrt{3}}/{2} \log _{ {\e}} ( {2}/{ {\e} \sqrt{3}})

\frac{\pi}{12}+ {\sqrt{3}}/{2} \log _{ {\e}} ( {2 \sqrt{3}}/{ {\e}})

\frac{\pi}{12}- {\sqrt{3}}/{2} \log _{ {\e}} ( {2 \sqrt{3}}/{ {\e}})

\frac{\pi}{12}+ {\sqrt{3}}/{2} \log _{ {\e}} ( {2}/{ {\e} \sqrt{3}})

JEE Mains 1-Feb-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 74 of 90

Marks: +1, -0

If y=y(x) is the solution curve of the differential equation ‌

+y‌tan‌x=x secx,‌‌0≤x≤‌

, y(0)=1, then y(‌

) is equal to

[1-Feb-2023 Shift 1]

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